16. Dapatkan nilai n dari persamaan berikut:
a. 3n = 243
b. 2n + 1 = 1/16
c. 4n = (–2)0
d. 48 ÷ 3 = n4
(Soal No. 14 Uji Kompetensi Bab Perpangkatan dan Bentuk Akar Buku BSE Matematika Kurikulum 2013 Semester 1 Kelas 9, Kemendikbud)
a. 3n = 243
b. 2n + 1 = 1/16
c. 4n = (–2)0
d. 48 ÷ 3 = n4
(Soal No. 14 Uji Kompetensi Bab Perpangkatan dan Bentuk Akar Buku BSE Matematika Kurikulum 2013 Semester 1 Kelas 9, Kemendikbud)
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a. 3n = 243
n = 243/3
n = 81
b. 2n + 1 = 1/16
2n + 1 = 1/24
2n + 1 = 2–4
n + 1 = –4
n = (–4) – 1
n = –5
c. 4n = (–2)0
4n = 1
n = 1/4
d. 48 ÷ 3 = n4
16 = n4
24 = n4
2 = n
n = 243/3
n = 81
b. 2n + 1 = 1/16
2n + 1 = 1/24
n + 1 = –4
n = (–4) – 1
n = –5
c. 4n = (–2)0
4n = 1
n = 1/4
d. 48 ÷ 3 = n4
16 = n4
24 = n4
2 = n
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